How do you find the asymptotes for $(x^2+ 3x − 4) /( 4x^2 − 7x + 3)$ ?

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Answer 1 · 2016-07-10T16:31:01

$lim_(x->+-oo)y = 1/4$

$lim_(x->3/4) y= +-oo$

Write as:

$y=(cancel((x-1))(x+4))/(cancel((x-1))(4x-3))" "=" "(x+4)/(4x-3)$

$lim_(x->+-oo)y = 1/4$

$lim_(x->3/4) y= +-oo$

Tony B

How do you find the asymptotes for (x^2+ 3x − 4) /( 4x^2 − 7x + 3)(x^2+ 3x − 4) /( 4x^2 − 7x + 3)?