How do you find the asymptotes for $(x^2 - 5x + 6)/(x - 3)$ ?

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Answer 1 · 2016-07-29T22:52:27

This function has no asymptotes. It has a hole at $(3, 1)$ .

$(x^2-5x+6)/(x-3)=(color(red)(cancel(color(black)((x-3))))(x-2))/color(red)(cancel(color(black)((x-3))))=x-2$

with exclusion $x != 3$

This is a straight line with a hole at $(3, 1)$

It has no asymptotes.

How do you find the asymptotes for (x^2 - 5x + 6)/(x - 3)(x^2 - 5x + 6)/(x - 3)?