How do you find the asymptotes for y=1/(2-x)?

1 Answer
Feb 16, 2016

y=0
and
x=2

Explanation:

As xrarr+-oo the 2 in the denominator becomes less and less significant and
lim_(xrarr+-oo) 1/(2-x) = 1/(+-oo) = 0
Therefore y=0 is an asymptote.

y=1/(2-x is defined for all values up to but not including x=2;
yrarr +-oo as xrarr2
Therefore x=2 is an asymptote.

Here is what the graph looks like:
graph{1/(2-x) [-10, 10, -5, 5]}