How do you find the asymptotes for y=22/(x+13)-10y=22x+13−10?

1 Answer
Shell
Oct 31, 2016

The horizontal asymptote is y=-10y=−10 and the vertical asymptote is x=-13x=−13.

Explanation:

Find the asymptotes for 22/(x+13) -1022x+13−10

The horizontal asymptote (HA) is given by the -10−10 term, so the HA is x=-10. In terms of transformations, the -10−10 shifts the graph down 1010.

The vertical asymptote (VA) is found by setting the denominator equal to zero. When the denominator is zero, the equation is undefined at that value of xx.

x+13=0x+13=0

x=-13x=−13 is the VA.

Alternatively, to find the HA, combine the two terms using a common denominator.

22/(x+13) -10 *frac{x+13}{x+13}22x+13−10⋅x+13x+13

(22-10x-130)/(x+13)22−10x−130x+13

(-10x-108)/(x+13)−10x−108x+13

In this case, the HA is found by comparing the degree of the numerator and denominator. If the degrees are the same, the HA is the leading coefficient of the numerator divided by the leading coefficient of the denominator.

y=(-10)/1=-10y=−101=−10 is the HA

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