How do you find the asymptotes for $y = \frac{7 x - 2}{x^{2} - 3 x - 4}$ $y= (7x-2) /( x^2-3x-4)$ ?

Question

How do you find the asymptotes for $y = \frac{7 x - 2}{x^{2} - 3 x - 4}$ $y= (7x-2) /( x^2-3x-4)$ ?

1 Answer

Impact of this question

1550 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-14T14:03:18

The asymptotes of any expression are found by defining what happens to the expression when $x \to \infty$ $x -> oo$ or $x \to - \infty$ $x-> - oo$ or when $y \to \infty$ $y->oo$

Explanation:

The asymptotes of any expression are found by defining what happens to the expression when $x \to \infty$ $x -> oo$ or $x \to - \infty$ $x-> - oo$ or when $y \to \infty$ $y->oo$
In this case $y = \frac{7 x + 2}{x^{2} - 3 x - 4}$ $y =(7x+2)/(x^2 - 3x - 4)$ or $\frac{7 x - 2}{(x - 4) (x + 1)}$ $(7x-2)/((x-4)(x+1))$

Hence when $x \to 4$ $x ->4$ or $x \to - 1$ $x -> -1$ then $y \to \infty$ $y -> oo$ . Therefore there are vertical asymptotes at $x = 4$ $x =4$ and at $x = - 1$ $x=-1$

$lim _( x-> +-oo) (7x-2)/(x^2-3x-4) = lim_(x->+-oo) 7/x =0$

Science

Math

Humanities

... and beyond

How do you find the asymptotes for $y = \frac{7 x - 2}{x^{2} - 3 x - 4}$ $y= (7x-2) /( x^2-3x-4)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the asymptotes for y= (7x-2) /( x^2-3x-4)y=7x−2x2−3x−4y= (7x-2) /( x^2-3x-4)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the asymptotes for $y = \frac{7 x - 2}{x^{2} - 3 x - 4}$ $y= (7x-2) /( x^2-3x-4)$ ?