How do you find the asymptotes for $y=(9x)/(9x+3)$ ?

Question

1383 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-27T08:14:59

Horizontal asymptote y=1
Vertical asymptotex=-1/3

Write $y= 1 + (-3)/(9x+3)$

This shows one horizontal asymptote y=1 and one horizontal asymptote 9x+3=0, that is x= -1/3

How do you find the asymptotes for y=(9x)/(9x+3)y=(9x)/(9x+3)?