How do you find the asymptotes for $y=x*ln[e + (1/x)]$ ?

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Answer 1 · 2018-06-27T06:32:28

Asymptote at $x=-1/e,0$

There is an asymptote at $x=0$ because at this point the function is undefined as $1/0$ is undefined. There is also an asymptote at

$e+1/x=0$ as the $ln$ function is undefined at $0$

$e+1/x=0 , ex+1=0 , ex=-1 x=-1/e$

How do you find the asymptotes for y=x*ln[e + (1/x)] y=x*ln[e + (1/x)] ?