Question

How do you find the asymptotes of `f(x)= (x^2+1)/(x+1)`?

Answer 1

`y=x-1` is an oblique asymptote.

Explanation:

`(x^2+1)/(x+1) = x-1+2/(x+1)` `" "`(by division)

So, as `x` increases or decreases without bound, the difference between `f(x)` and the `y` value of `y=x-1` approaches `0`.

So the graph of `f(x)` approaches the line `y=x-1`.