How do you find the average rate of change of y = 9x^3 - 2x2 + 6 over interval [-4,2]?

1 Answer
Jul 10, 2018

112

Explanation:

"the average rate of change of y over a closed interval"
[a,b]" is a measure of the slope of the secant connecting"
"the 2 points and is calculated using"

(f(b)-f(a))/(b-a)

"here "[a,b]=[-4,2]

f(b)=f(2)=9(2)^3-2(2)^2+6

color(white)(xxxxxxxx)=72-8+6=70

f(a)=f(-4)=9(-4)^3-2(-4)^2+6

color(white)(xxxxxxxxxx)=-576-32+6=-602

"average rate of change "=(70-(-602))/(2-(-4))

color(white)(xxxxxxxxxxxxxxxx)=672/6=112