How do you find the average rate of change of $y=sqrt(4x+1)$ over interval [0,2]?

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Answer 1 · 2015-10-12T00:27:26

The average rate of change is simply the slope of the line passing through the endpoints.

average rate of change = $(y(2)-y(0))/(2-0)$

$=(sqrt9-sqrt1)/2$ = $1$

hope that helped

How do you find the average rate of change of y=sqrt(4x+1)y=sqrt(4x+1) over interval [0,2]?