How do you find the average rate of change of #y=x^3+1# from #x=1# to #x=3#? Calculus Derivatives Average Rate of Change Over an Interval 1 Answer AJ Speller Sep 19, 2014 #(f(x+h)-f(x))/h=(f(b)-f(a))/(b-a)#, where #a# is the lower bound and #b# is the upper bound. Average rate of change #slope=(f(b)-f(a))/(b-a)=(f(3)-f(1))/(3-1)=((3)^3+1-((1)^3+1))/(3-1)=((27+1)-(1+1))/(3-1)=(28-2)/(3-1)=26/2=13# Point: #(3,28)# Point: #(1,2)# #y=mx+b# #2=13(1)+b# #2=13+b# #-11=b# #y=13x-11#, the secant line through the points #(3,28)# and #(1,2)#. Answer link Related questions How do you find the average rate of change of a function from graph? How do you find the average rate of change of a function between two points? How do you find the average rate of change of #f(x) = sec(x)# from #x=0# to #x=pi/4#? How do you find the average rate of change of #f(x) = tan(x)# from #x=0# to #x=pi/4#? How do you find the rate of change of y with respect to x? What is the relationship between the Average rate of change of a fuction and derivatives? What is the difference between Average rate of change and instantaneous rate of change? What does the Average rate of change of a linear function represent? What is the relationship between the Average rate of change of a function and a secant line? What does average rate of change tell you about a function? See all questions in Average Rate of Change Over an Interval Impact of this question 13289 views around the world You can reuse this answer Creative Commons License