Question

How do you find the center and radius for `X^2 + Y^2 = 13`?

Answer 1

centre = (0 , 0 ) and r = `sqrt13`

Explanation:

require to compare this equation with the standard form of the equation of a circle.

`(x - a )^2 + (y - b )^2 = r^2`

where (a , b ) represents the centre of the circle and r the radius

`X^2 + Y^2 = (X- 0 )^2 + (Y -0 )^2`

`r^2 = 13 rArr r = sqrt13`

hence centre = (0 ,0 ) and radius = `sqrt13`