Question

How do you find the center and radius of the circle `(x+4)^2+y^2=49`?

Answer 1

Center of the circle is `(-4,0)` and radius is `7`

Explanation:

Equation of a circle with center at `(h,k)` and radius `r` is given by

`(x-h)^2+(y-k)^2=r^2`

Hence `(x+4)^2+y^2=49`

`hArr(x-(-4))^2+(y-0)^2=7^2`

Hence center of this circle is `(-4,0)` and radius is `7`
graph{(x+4)^2+y^2=49 [-24.58, 15.42, -9.92, 10.08]}