How do you find the center and radius of the circle $(x+4)^2+y^2=49$ ?

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Answer 1 · 2016-10-11T09:31:48

Center of the circle is $(-4,0)$ and radius is $7$

Equation of a circle with center at $(h,k)$ and radius $r$ is given by

$(x-h)^2+(y-k)^2=r^2$

Hence $(x+4)^2+y^2=49$

$hArr(x-(-4))^2+(y-0)^2=7^2$

Hence center of this circle is $(-4,0)$ and radius is $7$
graph{(x+4)^2+y^2=49 [-24.58, 15.42, -9.92, 10.08]}

How do you find the center and radius of the circle (x+4)^2+y^2=49(x+4)^2+y^2=49?