How do you find the coordinates of the vertices, foci, and the equation of the asymptotes for the hyperbola (y3)225(x2)216=1?

1 Answer
Oct 24, 2016

The vertices are (2,8) and (2,2)
The foci are (2,3+41) and (2,341)
The equations of the asymptotes are (y=3+54(x3))
and (354(x3))

Explanation:

Looking at the equation it's an up-down hyperbola

The center of the hyperbola is (2,3)

The vertices are (2,8) and (2,2)

The slope of the asymptotes ares (54) and (54)

The equations of the asymptotes are (y=3+54(x3))
and (354(x3))

To calculate the foci, we need c=±16+25=41

The foci are (2,3+41) and (2,341)