How do you find the critical points and local max and min for #y=4x-x^2#?
1 Answer
Nov 23, 2016
Maximum at
Explanation:
Although we can use calculus sometimes an intuitive common sense approach is quicker and easier.
If
The function has a -ve coefficient of
graph{4x-x^2 [-10, 10, -5, 5]}
Using Calculus
At critical point,
To establish min or max we look at the 2nd derivative:
When