How do you find the definite integral of #13e^-(cos(x)) sin(x) dx# from #[ 0 , pi/2]#?

Question

1285 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-18T10:48:42

#int_0^(pi/2) 13*e^-cos x *sin x # # dx=8.21757#

#int_0^(pi/2) 13*e^-cos x *sin x # # dx #

#int 13 e^-cos x * sin x# #dx#= #13 e^-cos x#

Evaluating the integral from #0# to #pi/2#

#=13[e^-cos (pi/2) - e^-cos 0]#

#=13[e^0 - e^-1]#

#=13[1-e^-1]#

#8.21757#