Question

How do you find the definite integral of `int (1-2x-3x^2)dx` from `[0,2]`?

Answer 1

`int_0^2(1-2x-3x^2)d x=-10`

Explanation:

`int_0^2(1-2x-3x^2)d x=|x-2*1/2*x^2-3*1/3*x^3|_0^2`
`int_0^2(1-2x-3x^2)d x=|x-x^2-x^3|_0^2`
`int_0^2(1-2x-3x^2)d x=2-2^2-2^3`
`int_0^2(1-2x-3x^2)d x=2-4-8`
`int_0^2(1-2x-3x^2)d x`
`int_0^2(1-2x-3x^2)d x=-10`