Question

How do you find the derivative of `1/[16x+3]^2` using the chain rule?

Answer 1

`f'(x)=-32/(16x+3)^3`

Explanation:

`f'(x)=(16x+3)^-2`

According to the Chain Rule,
`f'(x)=-2(16x+3)^-3*stackrel"This term = 16."overbrace(d/dx[16x+3]`
`f'(x)=-32/(16x+3)^3`