How do you find the derivative of #(1+x)^(1/x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer bp May 13, 2015 # (1+x)^(1/x) [-1/x^2 ln(1+x) + 1/(x(1+x))]# Let y= #(1+x)^(1/x)# ln y= #1/x ln(1+x)#. Now differentiate, #1/y dy/dx= (-1/x^2) ln(1+x) + 1/x * 1/(1+x)# #dy/dx = (1+x)^(1/x) [-1/x^2 ln(1+x) + 1/(x(1+x))]# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 1620 views around the world You can reuse this answer Creative Commons License