How do you find the derivative of $\frac{1}{x^{3} - x^{2}}$ $1/(x^3-x^2)$ ?

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Answer 1 · 2017-01-29T13:47:09

$\frac{2 - 3 x}{x^{3} {(x - 1)}^{2}}$ $(2-3x)/(x^3(x-1)^2)$

$f'(x)=-(3x^2-2x)/(x^3-x^2)^2$

$=-(cancelx(3x-2))/(x^(cancel4^3)(x-1)^2)$

$=(2-3x)/(x^3(x-1)^2)$

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