How do you find the derivative of $(2t)^5$ ?

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Answer 1 · 2018-03-03T02:45:03

$d/dt[(2t)^5]=160t^4$

Take out the constant and apply the power rule:

The power rule states: $d/dt[t^n]=nt^(n-1)$

So:

$d/dt[(2t)^5]<=>2^5*d/dt[t^5]$

$=2^5*color(red)5t^(color(red)(5-1))$

$=2^5*5t^4$

$=160t^4$

How do you find the derivative of (2t)^5(2t)^5?