Question

How do you find the derivative of `2x^2+x-1`?

Answer 1

`dy/dx(2x^2+x-1)=4x+1`

Explanation:

Use the power rule `r(a)^(r-1)` and recall that the derivative of a constant is `0`

Therefore the derivative is,

`dy/dx=2*2x^(2-1)+1x^(1-0)-0`

`dy/dx=4x+1`