How do you find the derivative of #4cosxsiny=1#?
1 Answer
Sep 15, 2017
Explanation:
We have, using identities:
#siny = 1/(4cosx)#
#siny = 1/4secx#
Using implicit differentiation/known derivative, we get:
#cosy(dy/dx) = 1/4secxtanx#
Isolating the differential:
#dy/dx = 1/4secxtanxcosy#
Hopefully this helps!