How do you find the derivative of $[(4x ^ 2 + 7) ^2 (2x^3 + 1)^4]$ ?

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Answer 1 · 2015-10-09T15:26:32

$24x^2(4x^2+7)^2(2x^3+1)^3+16x(2x^3+1)^4(4x^2+7)$

Using the product rule, which will contain 2 power rules, we get :

$(df)/dx=(4x^2+7)^2*4(2x^3+1)^3*6x^2+(2x^3+1)^4*2(4x^2+7)*8x$

How do you find the derivative of [(4x ^ 2 + 7) ^2 (2x^3 + 1)^4][(4x ^ 2 + 7) ^2 (2x^3 + 1)^4]?