Question

How do you find the derivative of `(4x +x^-5)^⅓`?

Answer 1

`d/dx(4x+x^-5)^(1/3)=1/3(4x+x^-5)^(-2/3)*(4-5x^-6)`

Explanation:

Use the power rule : `d/dx[u(x)]^n=n[u(x)]^(n-1)*(du)/dx`

`therefore d/dx(4x+x^-5)^(1/3)=1/3(4x+x^-5)^(-2/3)*(4-5x^-6)`