How do you find the derivative of $(4x +x^-5)^⅓$ ?

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Answer 1 · 2016-02-21T18:54:19

$d/dx(4x+x^-5)^(1/3)=1/3(4x+x^-5)^(-2/3)*(4-5x^-6)$

Use the power rule : $d/dx[u(x)]^n=n[u(x)]^(n-1)*(du)/dx$

$therefore d/dx(4x+x^-5)^(1/3)=1/3(4x+x^-5)^(-2/3)*(4-5x^-6)$

How do you find the derivative of (4x +x^-5)^⅓(4x +x^-5)^⅓?