How do you find the derivative of $8 x^{2} + 9 x + 12$ $8x^2+9x+12$ ?

Question

How do you find the derivative of $8 x^{2} + 9 x + 12$ $8x^2+9x+12$ ?

2 Answers

Impact of this question

2321 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-14T12:56:21

$\frac{d}{d x} [8 x^{2} + 9 x + 12] = 16 x + 9$ $d/dx[8x^2+9x+12]=16x+9$

Explanation:

Remember that:

$\frac{d}{d x} [x^{n}] = n x^{n - 1}$ $d/dx[x^n]=nx^(n-1)$ if $n$ $n$ is a constant.

Therefore, the derivative is:

$8 \cdot 2 x^{2 - 1} + 9 \cdot 1 \cdot x^{1 - 1} + 12 \cdot 0 \cdot x^{0 - 1}$ $8*2x^(2-1)+9*1*x^(1-1)+12*0*x^(0-1)$

$\Rightarrow 16 x^{1} + 9 x^{0} + 0$ $=>16x^(1)+9x^(0)+0$

$\Rightarrow 16 x + 9$ $=>16x+9$

That is the answer!

Answer 2 · 2018-04-14T13:44:33

$16 x + 9$ $16x+9$

Explanation:

$differentiate each term using the power rule$ $"differentiate each term using the "color(blue)"power rule"$

$∙ x \frac{d}{d x} (a x^{n}) = n a x^{n - 1}$ $•color(white)(x)d/dx(ax^n)=nax^(n-1)$

$\Rightarrow \frac{d}{d x} (8 x^{2} + 9 x + 12) = 16 x + 9$ $rArrd/dx(8x^2+9x+12)=16x+9$

Science

Math

Humanities

... and beyond

How do you find the derivative of $8 x^{2} + 9 x + 12$ $8x^2+9x+12$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the derivative of 8x^2+9x+128x2+9x+128x^2+9x+12?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you find the derivative of $8 x^{2} + 9 x + 12$ $8x^2+9x+12$ ?