How do you find the derivative of $e^sinx$ ?

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Answer 1 · 2018-05-25T15:56:57

$y'=e^sin(x)*cos(x)$

Taking the logarithm on both sides we get
$ln(y)=sin(x)$
Differentiating this with respect to $x$ :
$1/y*y'=cos(x)$
so
$y'=e^(sin(x))*cos(x)$

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