How do you find the derivative of $f (x) = \frac{1}{2} x^{4} - 2 x^{3} + \frac{1}{3} x - 4$ $f(x)=1/2x^4-2x^3+1/3x-4$ ?

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Answer 1 · 2016-12-02T15:43:44

The answer is $= 2 x^{3} - 6 x^{2} + \frac{1}{3}$ $=2x^3-6x^2+1/3$

Here we are calculating the derivatives of powera of $x$ $x$

$(x^n)'=nx^(n-1)$

$f(x)=x^4/2-2x^3+x/3-4$

Then,

$f'(x)=(4x^3)/2-2*3x^2+1/3$

$=2x^3-6x^2+1/3$

How do you find the derivative of f(x)=1/2x^4-2x^3+1/3x-4f(x)=12x4−2x3+13x−4f(x)=1/2x^4-2x^3+1/3x-4?