How do you find the derivative of $f(x)=2/3x^3-x^2-24x-4$ ?

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Answer 1 · 2016-07-24T04:10:01

$f'(x) =3 xx 2/3x^(3 - 1) - 1 xx 2x^(2 - 1) - 1 xx 24x^(1 - 1) - 0 xx 4x^(0 - 1)$

$f'(x) = 2x^2 - 2x - 2$

Hopefully this helps!

How do you find the derivative of f(x)=2/3x^3-x^2-24x-4f(x)=2/3x^3-x^2-24x-4?