How do you find the derivative of $f(x)=6sqrtx+5cosx$ ?

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Answer 1 · 2017-02-16T13:10:40

$3/sqrtx -5sin x$

$f'(x) = d/dx (6sqrtx) + d/dx (5 cos x)$

= $6(1/2 1/sqrt x) -5 sin x$

= $3/sqrtx -5sin x$

How do you find the derivative of f(x)=6sqrtx+5cosxf(x)=6sqrtx+5cosx?