Question

How do you find the derivative of `f(x)=(8x^2-6)^-1`?

Answer 1

`(df)/(dx)=-(16x)/(8x^2-6)^2`

Explanation:

We use the chain rule here.

As `f(x)=(8x^2-6)^(-1)`

`(df)/(dx)=-1xx(8x^2-6)^(-1-1)xx(16x)` or

= `-1/(8x^2-6)^2xx(16x)`

= `-(16x)/(8x^2-6)^2`