How do you find the derivative of #f(x)=e^(2x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer 1s2s2p Feb 13, 2018 #f'(x)=2e^(2x)# Explanation: If #f(x)=e^(g(x))# then #f'(x)=g'(x)e^(g(x))# #g(x)=2x# #g'(x)=2# #f'(x)=g'(x)e^(g(x))=2*e^(2x)=2e^(2x)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 1302 views around the world You can reuse this answer Creative Commons License