Question

How do you find the derivative of `f(x) = e^x + e^(-x / 2)`?

Answer 1

`f'(x)=e^x-1/(2e^x)`

Explanation:

Rule : `d/dx e^(u(x))=e^u*(du)/dx`.

Application thereof :

`d/dx[e^x+e^(-x/2)]=e^x-1/2e^(-x)`