Question

How do you find the derivative of `f(x) = log_x e`?

Answer 1

Use change of base to write `f(x) = lne/lnx = 1/lnx = (lnx)^-1`

Explanation:

So `f'(x) = -(lnx)^-2 (1/x) = (-1)/(xln^2x)`