How do you find the derivative of $f(x)=x^2-3x-3x^-2$ ?

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Answer 1 · 2016-11-29T09:24:46

The derivative is a linear operator, so you can differentiate term by term using the general formula:

$(d(x^n))/dx =n x^(n-1)$

$(df)/dx =d(x^2-3x-3x^(-2))/dx=d(x^2)/dx-3d(x)/dx-3d(x^-2)/dx =$

$= 2x -3 +6x^(-3)$

How do you find the derivative of f(x)=x^2-3x-3x^-2f(x)=x^2-3x-3x^-2?