Question

How do you find the derivative of `f(x)=x^2+4x+8`?

Answer 1

`f^'(x)=2x+4`

Explanation:

Given -

`f(x)=x^2+4x+8`

`f^'(x)=(1 xx 2)x^(2-1)+(4 xx 1)x^(1-1)+0`

`f^'(x)=2x+4`