How do you find the derivative of $f (x) = x^{3} + 6 x^{2}$ $f(x) = x^3 + 6x^2$ ?

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Answer 1 · 2016-09-11T13:54:48

$3 x^{2} + 12 x$ $3x^2+12x$

$\frac{d}{d x} x^{3} + 6 x^{2}$ $d/dxx^3+6x^2$

Exponent rule: $\frac{d}{d x} x^{n} = n x^{n - 1}$ $d/dx x^n= nx^(n-1)$

$3 x^{3 - 1} + (6) 2 x^{2 - 1}$ $3x^(3-1)+(6)2x^(2-1)$

$3 x^{2} + 12 x$ $3x^2+12x$

How do you find the derivative of f(x)=x3+6x2f(x) = x^3 + 6x^2?