Question

How do you find the derivative of `f(y)=2y^3+4y^2`?

Answer 1

`f'(y)=6y^2+8y`

Explanation:

The question might seem strange because we are used to seeing functions defined in terms of some variable "`x`". But we can use any other letter, and it still works the same way.

Finding the derivative of `f(y)` with respect to `y` is exactly the same as finding the derivative of `f(x)` with respect to `x`.

`f(y)=2y^3+4y^2`

Multiply the coefficient of each term by the exponent of `y`, then lower the exponent by 1.

`f'(y)=3*2y^(3-1)+2*4y^(2-1)`

`f'(y)=6y^2+8y`