Question

How do you find the derivative of function `y=(sqrtx) *(x-3)^2`?

Answer 1

In this way:

`y'=1/(2sqrtx)*(x-3)^2+sqrtx*2(x-3)^(2-1)*1=`

`=(x-3)[(x-3)/(2sqrtx)+2sqrtx]=(x-3)((x-3+4x)/(2sqrtx))=`

`=((x-3)(5x-3))/(2sqrtx)`.