Question

How do you find the derivative of `g(t) = 1/t^(1/2)`?

Answer 1

`g'(t) = -1/(2t^(3/2))`

Explanation:

`g(t) = 1/t^(1/2) = t^(-1/2)`

Applying the power rule:

`g'(t) = -1/2 t^((-1/2-1)) = -1/2 t^(-3/2)`

`= -1/(2t^(3/2))`