How do you find the derivative of g(t)=t^2-4/t^3g(t)=t2−4t3?

1 Answer
Jim G.
Nov 28, 2016

g'(t)=2t+12/t^4

Explanation:

Express g(t) in the following form.

g(t)=t^2-4t^(_3)

differentiate each term using the color(blue)"power rule"

color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))

rArrg'(t)=2t+12t^(-4)=2t+12/t^4

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