Question

How do you find the derivative of `g(x)=1/sqrtx`?

Answer 1

see below

Explanation:

`g(x)=1/sqrtx`

`=>d/dxg(x)=d/dx(x)^(-1/2)`

Utilize the formula,

`d/dxx^n=nx^(n-1)`

`=>d/dx(x)^(-1/2)=-1/2x^((-1/2-1))=-1/(2xsqrtx)`