How do you find the derivative of $g(x)=root4(x)$ ?

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Answer 1 · 2017-01-23T08:11:03

The answer is $=1/(4root(4)(x^3))$

We use

$(x^n)'=nx^(n-1)$

$g(x)=root(4)x=x^(1/4)$

$g'(x)=1/4*x^(1/4-1)$

$=1/4x^(-3/4)=1/(4root(4)(x^3))$

How do you find the derivative of g(x)=root4(x)g(x)=root4(x)?