How do you find the derivative of #g(x)=root4(x)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Narad T. Jan 23, 2017 The answer is #=1/(4root(4)(x^3))# Explanation: We use #(x^n)'=nx^(n-1)# #g(x)=root(4)x=x^(1/4)# #g'(x)=1/4*x^(1/4-1)# #=1/4x^(-3/4)=1/(4root(4)(x^3))# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1236 views around the world You can reuse this answer Creative Commons License