How do you find the derivative of #g(x)=xsqrtx#? Calculus Basic Differentiation Rules Power Rule 1 Answer Andrea S. Dec 29, 2016 #d/(dx) xsqrt(x)= (3/2)sqrtx# Explanation: #xsqrt(x) = x*x^(1/2) =x^(3/2)# so #d/(dx) xsqrt(x) = 3/2x^(1/2) = (3/2)sqrtx# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 3226 views around the world You can reuse this answer Creative Commons License