How do you find the derivative of $h (s) = s^{\frac{4}{5}} - s^{\frac{2}{3}}$ $h(s)=s^(4/5)-s^(2/3)$ ?

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Answer 1 · 2017-02-17T10:55:14

$h'(s) = 4/(5 root(5)s) - 2/(3 root(3) s)$

$h(s)=s^(4/5)-s^(2/3)$

$h'(s) = 4/5 s^((4/5-1)) - 2/3 s^((2/3-1))$

$h'(s) = 4/5 s^((-1/5)) - 2/3 s^((-1/3))$

$h'(s) = 4/(5 s^((1/5))) - 2/(3 s^((1/3))$

$h'(s) = 4/(5 root(5)s) - 2/(3 root(3) s)$

How do you find the derivative of h(s)=s^(4/5)-s^(2/3)h(s)=s45−s23h(s)=s^(4/5)-s^(2/3)?