How do you find the derivative of #ln x^(1/5)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Ratnaker Mehta Jan 25, 2017 #1/(5x)#. Explanation: Using the Rule of Logarithm Function, #y=lnx^(1/5)=1/5lnx# #:. dy/dx=d/dx{1/5lnx}=1/5d/dx{lnx}=1/5(1/x)=1/(5x)#. Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 3648 views around the world You can reuse this answer Creative Commons License