How do you find the derivative of #logx^2#?
1 Answer
Jan 10, 2016
Explanation:
Use logarithm rules to rewrite the function as
#2logx#
Also, recall that
#2(lnx/ln10)#
If we want to differentiate this, remove the core function,
#2/ln10*lnx#
Finding the derivative:
#2/ln10*d/dx[lnx]#
#2/ln10*1/x#
#2/(xln10)#