How do you find the derivative of #root4(lnx)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shwetank Mauria Jun 16, 2016 #(df)/(dx)=1/(4x(root(4)lnx)^3)# Explanation: We use the chain rule here. As #f(x)=(lnx)^(1/4)# #(df)/(dx)=1/4xx(lnx)^(1/4-1)xx1/x# or #(df)/(dx)=1/4xx(lnx)^(-3/4)xx1/x# i.e. #(df)/(dx)=1/(4x(root(4)lnx)^3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 962 views around the world You can reuse this answer Creative Commons License