How do you find the derivative of $s = t sin t$ $s=tsint$ ?

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Answer 1 · 2017-03-06T14:33:17

$s'(t)=sint+tcost$

This will require the product rule for derivatives.

Recall that the product rule states that given a function that is the product of two other functions,

$s(t)=f(t)*g(t)$

its derivative is

$s'(t)=f'(t)*g(t)+f(t)*g'(t)$

For this expression,

$f(t)=t$
and
$g(t)=sint$

So,

$s'(t)=(1)*sint+t*cost$

$s'(t)=sint+tcost$

How do you find the derivative of s=tsints=tsints=tsint?