Question

How do you find the derivative of `sin^2(2x)`?

Answer 1

`4sin(2x)*cos(2x)`

Explanation:

Differentiate using chain rule:
`sin^2(2x)` can be rewritten as `(sin(2x))^2`
`2sin(2x)*cos(2x)*2`
`4sin(2x)*cos(2x)`