How do you find the derivative of ${sin}^{2} (2 x)$ $sin^2(2x)$ ?

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How do you find the derivative of ${sin}^{2} (2 x)$ $sin^2(2x)$ ?

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Answer 1 · 2015-11-07T17:07:03

$4 sin (2 x) \cdot cos (2 x)$ $4sin(2x)*cos(2x)$

Explanation:

Differentiate using chain rule:
${sin}^{2} (2 x)$ $sin^2(2x)$ can be rewritten as ${(sin (2 x))}^{2}$ $(sin(2x))^2$
$2 sin (2 x) \cdot cos (2 x) \cdot 2$ $2sin(2x)*cos(2x)*2$
$4 sin (2 x) \cdot cos (2 x)$ $4sin(2x)*cos(2x)$

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How do you find the derivative of ${sin}^{2} (2 x)$ $sin^2(2x)$ ?

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